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Equation Icon  ( 2) L2 (ξ + x2)(1 − x2)dx2 L2 (4 − m2x2 ) ξm − 43xm2- ( )2 γabdxadxb = -----m------(------4x2) + ------------2-------2----- dĪ• + 12 cos 𝜃dχ (4 − m2x2 ) ξm − 3m2-- (ξm + x )(1 − x ) + 1L2 (1 − x2 )(d 𝜃2 + sin2𝜃d χ2), (92 ) 4√ --- ( ) 2 ξmL2 (4 − m2x2 ) ξm − 4x22- ( ) hadxa = ± --------------------------3m--- d Ī• + 1cos 𝜃dχ − --2x---dx, (93 ) (ξm + x2)2(1 − x2 ) 2 ξm + x2