Equation Icon  { 2 1 2 2 2 ¯σ 0 = --- (2n + 1)(ωr + ω 𝜃) − (n + 1)κ 0 (113 ) 2n } [ 2 2 2 2 2 2 2 2]1∕2 ± ((2n + 1)(ω 𝜃 − ωr) + (n + 1)κ 0) + 4(ω r − κ 0)ω 𝜃 .