Equation Icon  h (1,1) = 4ma ai + ˆA(1,1)ωi + 5m ℰ ωˆij + 3ma a ωˆij, tt i i 3 ij 4 ⟨i j⟩ h (1ta,1) = Bˆ(1,1)ωa − 2m ˙aa + Cˆ(a1i,1)ωi + 𝜖aij ˆD (1j,1)ωi + 23m 𝜖aijℬjkˆωik, (1,1) (4 i (1,1) i 5 ij 3 ij) 4 i (22.38 ) h ab = δab 3maia + Kˆi ω − 9m ℰijˆω + 4ma ⟨iaj⟩ˆω + 3 mℰ ⟨aˆωb⟩i 38 ˆ (1,1) i j ˆ(1,1) i ˆ(1,1) − 9 m ℰab + 4ma ⟨aab⟩ + H abi ω + 𝜖i (aIb)j ω + F ⟨a ωb⟩.