Equation Icon  (2,−1) (2,−1) (1,0) ij h Btt = Aˆ − mHˆij ˆω , (2,−1) ˆ(1,0) i ˆ(2,−1) h Bta = − m(C i ˆω a + C a , ) ( ) (22.53 ) h (2,−1)= δ ˆK (2,−1) − 1m ˆH (1,0)ˆωij − m ˆA(1,0) + ˆK (1,0) ˆω + 2m ˆH (1,0)ˆω i + Hˆ(2,− 1). Bab ab 3 ij ab i⟨a b⟩ ab