Equation Icon  ( ) ˆA (2,− 1) = Kˆ(2,−1) − 8m ˆA(1,0) + ˆK (1,0) , (22.57 ) 3 Hˆ (2,− 1) = 2m Hˆ(1,0), (22.58 ) ij 3 ij