Equation Icon  1 ∫ ( ′′ ′ ′ ′ ′) h(α1)β = − --- ∇ μ′ G+αβαβ ∇ μh (1α)′β′ − h (1α)′β′∇ μG+αβα β dV ′ + h(1¯) 4π Σ αβ Int∫(Γ ) -1- ( α′β′ (1) (1) α′β′ + ) ′ (1) = − 4π G αβ E α′β′[h ] − hα′β′E [Gαβ] dV + h¯Σαβ, (23.1 ) Int(Γ )