Equation Icon  (1) 2m--( 3 i 3 2 ij 15 2 ¯α 1 2 i 5 2 ij) i tail h tt = s 1 + 2saiω + 8s aiajω − 8 s ˙a¯αu + 3s ˙aiω + 6s ℰijω + (1 + 2saiω )h00 +shtailωi + O (s2), (23.9 ) 00i h (1ta) = 4maa − 23msR0iaj ωij + 2ms ℰaiωi − 2ms a˙a + (1 + saiωi)ht0aail+ shta0iailωi + O (s2), (23.10 ) 2m ( ) h (1a)b = ---- 1 − 12saiωi + 38s2aiajωij + 18s2˙a¯αu¯α + 13s2a˙iωi − 16s2ℰijωij δab + 4msaaab s ij tail tail i 2 − 23msRaibj ω − 4ms ℰab + hab + sh abiω + O (s ). (23.11 )